Agroup of children, adults, and senior citizens attended three different art exhibits that have different ticket prices for each age group. let c represent the number of children, a represent the number of adults, and s represent the number of senior citizens. the system represents the cost of each type of ticket and the total cost of the tickets for all three exhibits. what are the number of children, adults, and seniors that attended these three exhibits? 6c + 7a + 2s = 990 3c + 3a + 4s = 430 2c + 4a + 4s = 480 a) c = 120, a = 30, s = 30 b) c = 20, a = 40, s = 70 c) c = 100, a = 50, s = 5 d) c = 100, a = 50, s = 20

Option D) c = 100, a = 50, s = 20

Step-by-step explanation:

we have

6c + 7a + 2s = 990  -----> equation A

3c + 3a + 4s = 430  -----> equation B

2c + 4a + 4s = 480 ----> equation C

Isolate variable s in equation A

2s = 990 -6c-7a  

s=495-3c-3.5a -----> equation D

Substitute equation D in equation B and in equation C

3c + 3a + 4(495-3c-3.5a) = 430

3c + 3a +1,980-12c-14a= 430

-9c-11a=-1,550 -----> equation E

2c + 4a + 4(495-3c-3.5a) = 480

2c+4a+1,980-12c-14a=480

-10c-10a=-1,500 -----> 10c+10a=1,500 -----> equation F

Solve the system of equations E and F by graphing

using a graphing tool

Let

The variable c -----> the x-axis

The variable a ----> the y-axis

The solution is the point (50,100)

see the attached figure

so

c=50, a=100  

Find the value of s

s=495-3(50)-3.5(100)=-5 -----> is not make sense

therefore

Let

The variable c -----> the y-axis

The variable a ----> the x-axis

The solution is the point (50,100)

so

a=50, c=100  

Find the value of s

s=495-3(100)-3.5(50)=20

therefore

The solution is

c=100,a=50,s=20

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

the answer is y = 11.54

hope this : )