Compare the functions shown below: f(x) = 3 cos 2x + 4 g(x) cosine graph with points at 0, 3 and pi over 2, 0 and pi, negative 3 and 3 pi over 2, 0 and 2 pi, 3 h(x) x y −6 −11 −5 −6 −4 −3 −3 −2 −2 −3 −1 −6 0 −11 which function has the greatest maximum y-value?

See the attached figures.

Figure_1 is a clear presentation of the problem and contains the graph of the function g(x), while figure_2 contains of the graph of f(x) and h(x).

As shown in the figures.

f(x) representing a cosine function and it has maximum y-value = 7

g(x) representing a cosine function and it has maximum y-value = 3

h(x) representing a parabola function and it has maximum y-value = -2

So, The function with the greatest maximum y-value is f(x)

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

27/4x^6 y^8

step-by-step explanation:

4(3x^2y^4)^3 (2x^3y^5)^4

=

108x^6 y^12 /16x^12 y^20

=

108 /16x^6 y^8

=

27 /4x^6 y^8