Point x is located at (2, -6) and point z is located at (0,5) find the y value that is located 1/5 the distance from point x to point z a. -3.6 b. -3.8 c. -4 d. -4.2

To go from point X to point Z, the y value starts at -6 and turns into 5. So we go from y = -6 to y = 5. This is a distance of 11 units. You can count out the vertical spaces or subtract to get |-6-5| = |-11| = 11, or you can do |5-(-6)| = |5+6| = |11| = 11.

Divide this vertical distance (11) by 5, which is the same as multiplying by 1/5 = 0.2, and you get 11/5 = 11*(1/5) = 11*0.2 = 2.2

The last step is to then add that result (2.2) to the y coordinate of x so we move 1/5th of the way along the line XZ, so we'll have -6+2.2 = -3.8

Choice B) -3.8

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explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3