Points d, e, and f are collinear and de: df= 2/5. point e is locate at (-3,2), point f is located at (-3,-4). what is the coordinate point of point d?

DE : DF = 2 : 5

So, DE = 2 parts and DF = 5 parts

EF = DF - DE

    = 5 - 2

    = 3 parts

DE : EF = 2 : 3

Let D be (x, y).

Then, the point E divides the line segment DF internally in the ratio 2 : 3.

So, E is

But, it is given that E is (-3, 2).

Therefore,

3x - 6 = -15 and 3y - 8 = 10

3x = -9 and 3y = 18

x = -3 and y = 6

Hence, D is (-3, 6)