What is the nth term of -4,-3,0,5,12,21,32?

The first set of differences is   1,3,5,7,9,11

second set of difference = 2 so this is a quadratic sequence  with first term n^2

subtract n^2 from the sequence:-

-4  -  3    0     5

1      4     9    16

-5   -7    -9     -11  

This last series is an AP with nth term = - 5-2(n - 1)

so nth term  for original series is n^2 - 5 - 2(n - 1)

= n^2  - 2n  - 3  answer

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.