What is the height of an isosceles trapezoid, if the lengths of its bases are 5m and 11m, and the length of a leg 4m. show your work. you!

An isosceles trapezoid has 2 parallel sides and equal non-parallel legs. The height of the isosceles trapezoid is 2.65 m

Because the trapezoid is isosceles, the 2 legs of the trapezoid will be equal.

I have added an attachment that represents the given trapezoid.

From the attachment, we have:

--- length of the leg

---- base of the triangle formed by the leg of the trapezoid

The height (h) is calculated using the Pythagoras theorem as follows:

So, we have:

Collect like terms

Take square roots of both sides

Hence, the height of the trapezoid is 2.65 m

Read more about isosceles trapezoid at:

link

Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,

Consider right triangle ABE, by the Pythagorean theorem

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p