Luka has a bag containing 5 socks: 3 red, 1 white, and 1 black. he draws 1 sock out of the bag, replaces it, and then draws another sock. what is the probability that he will draw a black sock and then a red sock, p(black, then red)?

the probability that he will draw a black sock and then a red sock, P(black, then red) is:

                 3/25=0.12

Step-by-step explanation:

Luka has a bag containing 5 socks: 3 red, 1 white, and 1 black.

Let A denote the event of drawing a first black sock.

and B denote the event of drawing a second red sock.

Hence, A∩B denote the event of drawing a black and then a red sock.

As the drawing of a second sock is done by replacement.

Hence, the probability of two events is independent.

i.e. P(A∩B)=P(A)×P(B)

Now,

P(A)=1/5

(Since there are 1 black sock out of total 5 sock)

and P(B)=3/5

(Since there are a total of 3 red socks out of total 5 sock)

Hence,

P(A∩B)=(1/5)×(3/5)=3/25

               Hence, the probability is:

                   3/25=0.12

table 3 represents a direct variation function. : )

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40