Caught speeding suppose police set up radar surveillance on the stanford street described in exercise 18. they handed out a large number of tickets to speeders going a mean of 28 mph, with a standard deviation of 2.4 mph, a maximum of 33 mph, and an iqr of 3.2 mph. local law prescribes fines of $100, plus $10 per mile per hour over the 20 mph speed limit. for example, a driver convicted of going 25 mph would be fined 100 + 10152 = +150. find the mean, standard deviation, maximum, and iqr of all the potential fines.

The mean would be 100+10*(28-20)=$180

The max would be 100+10*(33-20)=$230

The IQR is $205-$135=$70

Using a graphing calculator, the standard deviation is $38.94.

the probability is 0

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°