How do you do make sure you show !

We can only use two at a time for the time being.

-6a - 1 ≥ 3a - 10

add 10

-6a + 9 ≥ 3a

add 6a

9 > 9a

divide

1 ≥ a

Now we know a is less than 1 and can fill all a's with 1 in order to find the value of z.

-2z + 3 ≥ 6 * 1 - 1

add 1

-2z + 4 ≥ 6

Subtract 4

-2z ≥ 2

Divide by -2

z ≥ 1

z is ≥ 1, and a is ≤ 1

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

proportions are fractions that equal to each other. so if two fractions are the same, they are proportional.

let's check the answers to see if they are proportional.

question a is not proportional because you can't turn 1.5/3 to 3/9. if you try to multiply 1.5/3 by 2 or 3, you wont get 3/9. it's impossible to make the fractions the same.

question b is not proportional because you can't turn 22/33 to 4/6. 33 can't go into 6.

question c is proportional because when you multiply 2 and 3 by 71, you would get 142/213, and those fractions equal to each other

question d is proportional because when you divide 14 and 7 by 2, you would end up with 7/3.5, and those fractions equal to each other.