Math (use first pic for first two questions.) 1. what might the creator of this graph want the reader to conclude? ·the car dealer sold twice as many cars in april as in january. ·the car dealer sold the most cars in january. ·the car dealer's business is expanding very rapidly. ·the car dealer sold three times as many cars in march as in february. 2. what is one way to make this graph less misleading? · use wider bars for each month. · start the y-axis at 50 and use an interval of 1. ·use different colors for each month. ·start the y-axis at zero and use an interval of 5 or 10. (use second pic for this question.) 3. the camera shop wants to use the measure of central tendency that expresses how successful they are in selling cameras. which measure of central tendency should they choose? ·mean ·interquartile range ·mode ·median

Regarding the first question, the scale and the fact that the graph starts at 50 and not at 0 on the vertical axis, shows a deceptive growth trend. Therefore, the creator of this graph wants the reader to conclude that "The car dealership business is expanding very quickly"

In the second question, using wider bars, different colors or an interval of 1 will not make the graphic stop being misleading. Therefore the correct option is the fourth one: Start the y axis at zero and use an interval of 5 or 10. In the attached image the same graphic is shown but with these changes made and the difference is clearly noticed.

In the third question, if The Camera Shop wants to use the measurement of the central tendency that expresses how successful they are in the sale of cameras should consider that the data present high dispersion. For example, in February the value is of 21 and in December the value is of 125. The mean is a sensitive measure to the extreme values, for that reason of all the measures of central tendency cited the mean is the one that gives a higher result and for that may be the ideal to present to management the success of sales:

mean = 63.16

interquartile range = 47.5

mode = 35

median = 59.5

=

x=0.8898305 is the answer to that equation