Describe how you decide where the clock hands should point (2: 30 & 2: 50)?

It would be 2:30 if the little hand is on the 2 and the big hand is on the 6.
It would be 2:50 if the little hand is on the 2 and the big hand is on the 10.
                                                           I hope this helped :)

You decide where the clock hands are by knowing what each hand does. The small hand represents the hour while the big hand represents minutes. For the time 2:30 look for the numbers 2 and 3 the small hand should be in the middle and the big hand should be on the 6 which represents 30, keep in mind that the minutes go by 5 for example each whole number on the clock adds on by 5 the five times table would be helpful for this. For 2:50 the small hand should be closer to 3 but not on 3 and the big hand also known as minutes hand should be on 10.

Hope This Helps ;)

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

Ithink the answer is a