From plato triangle abc is dilated by a scale factor of 4 to form triangle a′b′c′. what are the coordinates of vertex a', vertex b', and vertex c'? (that is the picture)

The coordinates of vertex A', vertex B' and vertex C' are (-8, 4) , (-12, 12) and (-4, 12) respectively.

Explanation

According to the given diagram of triangle ABC, the co ordinates of the vertices are: and

If triangle ABC is dilated by a scale factor of 4 to form triangle A'B'C' , then we need to multiply each co ordinate by the scale factor of 4.

So, the co ordinate of A' will be:

the co ordinate of B' will be: and

the co ordinate of C' will be:

its 4 because 2 times 2 is 4, if you double the number two you get four

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3