Arectangular auditorium seats 2709 people. the number of seats in each row exceeds the number of rows by 20. find the number of seats in each row.

Let's assume

number of seats in each row =x

we are given

The number of seats in each row exceeds the number of rows by 20

number of seats = number of rows +20

x = number of rows +20

so, number of rows =x-20

total number of seats = (number of seats in each row)*(number of rows)

so, we can plug values

and we get

now, we can solve for x

since, number of seats can not be negative

so, number of seats in each row is 63.....................Answer

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: