Mike shoots a large marble (marble a, mass: 0.05 kg) at a smaller marble (marble b, mass: 0.03 kg) that is sitting still. marble a was initially moving at a velocity of 0.6 m/s, but after the collision it has a velocity of −0.2 m/s. what is the resulting velocity of marble b after the collision? show how you did this?

Answer

1.333 m/s

Explanation

The momentum before collision and after collision is always conserved.

m₁v₁ = m₂v₂

(0.05×0.6) + (0.03×0) = (0.03 × v) + (0.05 × -0.2)

0.03 + 0 = 0.03v - 0.01

0.03v = 0.03+0.01

0.03v = 0.04

v = 0.04/0.03

  = 4/3

   = 1.333 m/s

answer: $34.31

step-by-step explanation:

$11.99 x 3 = $35.97

$35.97 - 10% = $32.37

$32.37 + 6% = $34.31