Line cd passes through points c(3, –5) and d(6, 0). what is the equation of line cd in standard form?

Slope =   (y₂- y₁) / (x₂- x₁)

Points  C( 3, -5) and D (6, 0)  compare to (x₁, y₁) and  (x₂, y₂)

Slope = (0 - -5) / (6- 3)  =   (0+5) / (3) =  5/3

Slope = 5/3

Equation of line given a slope and point,   y - y₁ = m(x - x₁)

m = 5/3,    let point C( 3, -5) = (x₁, y₁)

  y -  - 5 =  (5/3) (x - 3)
 
  y + 5  = (5/3)(x - 3)

   3(y + 5) = 5(x - 3)
  
    3y + 15 = 5x - 15

     3y =  5x - 15 - 15

     3y = 5x - 30

Hence the equation of the line is 3y = 5x - 30