Find the midpoint of the segment with endpoints of 6 + 3i and −12 − 5i.

The midpoint of the segment with endpoints of 6 + 3i and −12 − 5i in complex form is -3 - i

Given the complex numbers  6 + 3i and −12 − 5i. We can write it in coordinate form (x. y)

x is the real part

y is the imaginary part

For the complex number 6 + 3i. the coordinate point will be (6, 3)

For the complex number -12 - 5i. the coordinate point will be (-12, -5)

Get the midpoint of both coordinates

Hence the midpoint of the segment in complex form is -3 - i

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for the imaginary plane the y-axis is the imaginary axis, therefore, 6 + 3i and -12 - 5i, is really just (6, 3) and (-12, -5).

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5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116