Ahelicopter above the ground is descending at 3.5 m/s. it drops a package from rest (relative to the helicopter). just before it hits the ground the package is falling at a rate of 13.4 m/ s relative to the ground. find the velocity of the package relative to the helicopter.

We are given that helicopter is descending at 3.5 m/s and a package is dropped from helicopter.

Its speed relative to helicopter is 0, that means it is started with the same speed as helicopter that is 3.5 m/sec relative to ground.

And when it reaches ground, its speed is 13.4 m/sec relative to ground.

Packet speed relative to helicopter = packet speed - helicopter speed

                                          = 13.4 - 3.5 = 9.9 m/sec

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70