Find the average rate of horizontal change of the ball the 1.6 sec.

a)

the average speed, well it does 10 ft in 1.6 secs, so is simply their quotient, 10/1.6 = 6.25 ft/s on average.

b)

over the horizontal, well, it covered horizontally 9.25 ft in those 1.6 secs, so their quotient is 9.25/1.6 = 5.78125 ft/s on average.

c)

we don't know the vertical distance, but

so, it covered vertically about 3.8 ft in those 1.6 secs, so then 3.8/1.6 = 2.375 ft/s on average

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2