what value(s) of k, where k is an interger, will allow each quadratic equation to be solved by factoring? x² +kx = 8

The factored form of the equation x²+kx=8 would be (x+a)(x+b)=0, with whatever values of a and b make the equation equivalent to x²+kx-8=0.

So we get k=a+b and ab=(-8).

Possible integer factors of -8 are:

1,-8 or -1,8, giving k = -7 or 7 (where's the plus-or-minus?)

2,-4 (k=-2) or -2,4 (k=2)

So possible values of k are -7, -2, 2, 7.

a

step-by-step explanation:

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)