Mathematics, 11.07.2019 09:00 india73
Ireally don’t understand this and just need an explanation of how to do it.
Answers: 1
![\bf ~\hspace{12em}\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{2n}{-3n\cdot -2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{-2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n\cdot -n}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n}\cdot \cfrac{1}{-n}](/tpl/images/0076/5552/6be79.png)
![\bf \cfrac{1}{-3n}\cdot \boxed{1}\cdot \cfrac{1}{-n}\implies \cfrac{1}{-3n\cdot -n}\implies \cfrac{1}{3n^2} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4\implies \left( \cfrac{1}{3n^2} \right)^4\implies \stackrel{\textit{distributing the exponent}}{\cfrac{1^4}{3^4n^{2\cdot 4}}}\implies \cfrac{1}{81n^8}](/tpl/images/0076/5552/00a52.png)
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