A400 foot long fence has posts that are placed 8 feet on center. that is the distance between the centers of two adjacent posts is 8 feet. if the fence begins and ends with a post, how many posts are needed for the fence?

The total length of the fence in feet = 400 feet

Posts are required at a distance of 8 feet

Total number of posts required = 400/8 = 50 posts

The 50 posts will include the post at the end since the last post will be placed at the 400 feet position which would mark the end of the fence.

Additionally, one more post will be required at the beginning since the first post will be placed at 8 feet from the start.

So total number of posts = 50 + 1 = 51 posts

Total number of posts required for the fence if it begins and ends with a post = 51 posts

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb