Find the area of the irregular figure

I got the answer of 432units^2

Since the length of the side and height are the same, 25, I subtracted 4 from 25, resulting in 21. To find the area of a of the missing triangle on the left side of the shape.

21 * 16, which is the length of the base results in 336/2 by using the triangle formula is 168.

The other smaller missing triangle on the right, I subtracted 15 from 25 to get the missing height of the triangle which is 10.

h=10
The base would be 10, the same length parallel to the base.

h=10 b=10

10*10=100/2 = 50

Add 168 and 50 together to get 218, the added areas of the two missing triangles.

I got the total area of the "square" by multiplying 26 by 25. L*W

26*25 = 650

Subtracted 218 from 650 to get 432.

Where m is the slope of the line and b is the y-intercept of the line, or the y-coordinate of the point at which the line crosses the y-axis. to write an equation in slope-intercept form, given a graph of that equation, pick two points on the line and use them to find the slope. this is the value of m in the equation.