△abc with vertices at a(−1,−1) , b(4,−4) , and c(2,−6) is dilated by a scale factor of 32 to create △a′b′c′ . the center of dilation is the point (5, −6) . what are the coordinates of vertex b′ ?

When D is the center of dilation, and k is the dilation factor, the image point is

... B' = k(B -D) +D

Filling in the given values, we have

... B' = 32((4, -4) -(5, -6)) +(5, -6)

... = 32(-1, 2) +(5, -6)

... = (-32, 64) +(5, -6)

... B' = (-27, 58)

6.5

step-by-step explanation:

you said it was in the question

~courtney

can you rephrase the question ? it is unclear : -)

step-by-step explanation: