Roger can run one mile in 18 minutes. jeff can run one mile in 15 minutes. if jeff gives roger a 1 minute head start, how long will it take before jeff catches up to roger?

Alright, lets get started.

Roger can run one mile in 18 minutes.

Jeff can run one mile in 15 minutes.

Suppose in x minutes, they both will catch up.

Roger runs in 18 minutes = 1 mile

So, Roger will run in 1 minute = miles

So, Roger will run in x minutes = miles

Jeff runs in 15 minues = 1 mile

So, Jeff will run in 1 minute = mile

As Jeff gives roger a 1 minute head start, means Jeff will have x-1 minute time to run

So, Jeff will run in (x-1) minute =

As both are cathing up means they both runs same distance, means

Cross Multiplying

x = 6 minutes

So for calculating distance =

Distance = miles

It means it will take 1/3 or 0.33 miles before jeff catches up to roger.   :   Answer

Hope it will help :)

right

step-by-step explanation:

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap