Anature museum has 2008 specimens of early birds, some with 2 wings and some with 4 wings. the specimens have a total of 4038 wings. how many specimens are there with each number of wings?

Answer:

Step-by-step explanation:

Given :

Number of specimens in the museum =2008 specimens of early birds, Some with 2 wings and some with 4 wings.

Total number of wings the specimen have=4038

To Find:

Number of birds with 2 wings=?

Number of birds with 4 wings=?

Solution:

Let the number of birds with 2 wings be n,

then number of birds with 4 wings will be 2008 – n birds.

Now, total number of wings = 4038 wings  

=>2 wings x number of birds with 2 wings + 4 wings x number of birds with 4 wings = 4038 wings

=> 2 x n + 4 x (2008 – n) = 4038  

=>2n + 4 x 2008 – 4n = 4038  

=>2n + 8032 – 4n = 4038  

=>2n – 4n = 4038 – 8032  

=>- 2n = - 3994  

=>2n = 3994  

=>

=>n = 1997  

So, 1997 birds has 2 wings, then, 2008 – 1997 = 11 birds has 4 wings.

first, let's see what the pattern is.

58 - x = 47

46 - x = 36

x = 9

so this means that the term after 25 is 25 - 9:

the next term in the sequence is 16.