The present cost of a car is $9,000. the cost of the car depreciates at the rate of $1000 per year. part a. write a function to show the cost of the car f(t) after t years. part b. what is the total cost of the car after 3 years? part c. if the cost of the car was $500 less than the present cost, what would be the cost of the car after 5 years?

A. f(t)=9000-1000t; Since 9000 is the number we start on, that is written as the constant. And since the value decreases by $1000 each year, we can put the $9000 it costs currently and will decrease by $1000 per year (t), this can be written as the function f(t)=9000-1000t

B. $6000; Just plug 3 into the equation to find the answer.

f(t)=9000-1000(3)

f(t)=9000-3000

f(t)= 6000

It costs $6000 after three years

C. $3500; To solve this just subtract 500 from 9000 to get 8500, and plug this in as the constant in our function.

f(t)=8500-1000(5)

f(t)=8500-5000

f(t)=3500

The answer is $3500

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step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2