Assume the weight of a randomly chosen american passenger car is a uniformly distributed random variable ranging from 2,500 pounds to 4,500 pounds. (a) what is the mean weight of a randomly chosen vehicle?

Let X= weight of the passenger car

a/q, X is u(2500,4500)

we know that mean= a+b/2

so a=2500, b=4500

hence, mean=2500+4500/2

=3500 pounds

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it