Hypotenuse of 15 and opposite of 12for this triangle what is the cos

right triangle with side "a" = 12 and hypotenuse "c" = 15

cos(∠A)

The Pythagorean theorem tells you

... b = √(c² - a²) = √(225 - 144) = √81 = 9

The definition of the cosine tells you

... cos(A) = b/c = 9/15

... cos(A) = 3/5 . . . . . . reduce the fraction

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

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step-by-step explanation: