What is the percent increase in production if the machine runs for 7 days a week instead of 5 days a week

Assuming the machine's output is proportional to the time it runs, the increase would be

... (amount of increase)/(original amount) × 100%

... = (7 - 5)/5 × 100%

... = (2/5)×100%

... = 40% . . . . the increase if the machine runs 7 days instead of 5

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step-by-step explanation:

yes

step-by-step explanation:

they have to be opposite and reciprocal of eachother.