Find two consecutive numbers whose sum is 115

Let's call the first number x. We know that the second number is consecutive (which means it comes right after the first number), so it's going to be x + 1.

We know when you work out the sum of these two numbers, it equals 115, so now you can form an expression:

x + (x + 1) = 115

Now you just need to simplify and combine the similar terms:

2x + 1 = 115

Now subtract 1 from both sides:

2x = 114

And finally, divide by 2 on both sides to isolate the x:

x = 57

Now that you know x = 57 (where x is the first number), you know that the second number is going to be 1 more than that (as it's consecutive). So it's going to 58.

Your two numbers are 57 and 58. And when you add them together, you'll get 115 (as 57 + 58 = 115).

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