When using a perpendicular director, why must the compass opening be greater than 1/2 the length of the segment

Because you want to draw 2 arcs ( by putting the point of the compass on each end of the line ) that intersect . If the opening was 1/2 or less than 1/2 of the length they would not intersect.

answer: i don't understand. what are the options

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.