Find four consecutive even integers such that the sum of twice the first, five times the second, and four times the third divided by three the fourth equals 3.

2x + 5(x + 2) + 4(x + 4) / 3(x + 6) = 3

11x + 26 / 3x + 18 = 3

11x + 26 = 9x + 54

2x = 28

x = 14

The integers are 14, 16, 18 and 20 Answer

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0

i think c. but don't trust it.

step-by-step explanation: