Craig runs a clothing store. he has decided to apply a markdown of 30% to one item in order to draw customers into the store, and he will apply a markup of 25% to three different items, which he hopes the customers will purchase after purchasing the marked-down item. he has chosen four candidates for this process: a leather jacket with an initial cost of $112.75, a blazer with an initial cost of $76.85, a pair of boots with an initial cost of $134.50, and a wristwatch with an initial price of $89.65. after applying the changes, the total cost of purchasing one of each item is $29.46 more than it was before applying the changes. which item was marked down?

The solution to this problem is trial and error. You know that if you have a total cost of purchasing one of each item, it will be $29.46 more than the total cost.

Add the three items before markup or markdown = $112.75+$76.85+$134.50+$89.65 = $423.75

So, apply markup to the leather jacket, blazer and wristwatch and apply mark down to the boots and you will get.

$112.75(1.25) + $76.85(1.25) + $134.50(1-0.30) + $89.65(1.25) = $443.21

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

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step-by-step explanation: