Let the universal set, s, have 66 elements. a and b are subsets of s. set a contains 19 elements and set b contains 34 elements. if sets a and b have 10 elements in common, how many elements are in neither a nor b?

The cardinality of the union between two sets is given by

In fact, if an element is in both A and B, it is counted in both N(A) and N(B), so we're counting it twice. By subtracting the cardinality of the interserction, we're taking back one of these "extra-counted" element, and the count is correct. In your case, the numbers are

This means that the two sets cover, without repetitions, 43 of the 66 elements in the sets. So, there are

elements which are in neither A nor B

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !

your answer is  

a.

5

step-by-step explanation: