)a rectangle has perimeter 40 feet and an area of 96 square feet. find the dimensions of the rectangle assuming the width is smaller than the length.

w=P

4+1

4P2﹣16A=40

4+1

4·402﹣16·96=12ft

w=P

4﹣1

4P2﹣16A=40

4﹣1

4·402﹣16·96=8ft

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

54 is the anser you are looking for