My teacher won't me and i don't understand how to do this or the answer collecting rationale numbers like terms -6 1/3 -1/2 (1/2+y 2/3n - 3/4n + 1/6n + 2 2/9n

Final result :

-12y2n - 67n - 1482

———————————————————

72

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "y2" was replaced by "y^2".

Step by step solution :

Step 1 :

22

Simplify ——

9

Equation at the end of step 1 :

61 1 1 (y2) 3 1 22

(0-——)-(—•—+(————•n))-(—•n))+(—•n))+(——•n)))

3 2 2 3 4 6 9

Step 2 :

1

Simplify —

6

Equation at the end of step 2 :

61 1 1 (y2) 3 1 22n

(0-——)-(—•—+(————•n))-(—•n))+(—•n))+———))

3 2 2 3 4 6 9

Step 3 :

3

Simplify —

4

Equation at the end of step 3 :

61 1 1 (y2) 3 n 22n

(0-——)-(—•—+(————•n))-(—•n))+—)+———))

3 2 2 3 4 6 9

Step 4 :

y2

Simplify ——

3

Equation at the end of step 4 :

61 1 1 y2 3n n 22n

(0-——)-(—•—+(——•n))-——)+—)+———))

3 2 2 3 4 6 9

Step 5 :

1

Simplify —

2

Equation at the end of step 5 :

61 1 1 y2n 3n n 22n

(0-——)-(—•—+———)-——)+—)+———))

3 2 2 3 4 6 9

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.