A50-foot flagpole is at the entrance of a building that is 300 feet tall. if the length of the flagpoles shadow is 30 feet at a certain time of day , how long is the building’s shadow at that time?

The building is 300/50 = 6 times as high as the flagpole, so we expect its shadow to be 6 times as long: 6×30 ft = 180 ft.

answer: apothems is your answer

step-by-step explanation: hope u get it right

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.