The sum of three consecutive integers is 393. find the integers.

Remark

Consecutive numbers are given as

x , x + 1 , x + 2

when they are added together you get x + x + 1 + x + 2 = 3x + 3

3x + 3 = 393 Subtract 3 from both sides.

3x = 393 - 3

3x = 390 Divide by 3

x = 390/3

x = 130

So the three numbers are

130

131

132

Let x represent the first integer

then the second integer is x + 1

and the third integer is x + 2

(x) + (x + 1) + (x + 2) = 393 the sum of the 3 integers is 393

3x + 3 = 393 added like terms

3x = 390 subtracted 3 from both sides

x = 130 divided both sides by 3

since x = 130, then x + 1 = 131, and x + 2 = 132

130, 131, 132

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step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

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