One bell rings at an interval of every 10 minutes and a second bell rings at an interval of every 12 minutes how many minutes must go by for the bells to ring at the same time? how many times would you hear them ringing at the same time if 240 minutes went by?

Find the Least Common Multiple (LCM) of 10 and 12

10 = 2 x 5

12 = 2 x 2 x 3

LCM = 2 (5 x 2 x 3) = 60

60 minutes, which occurs 4 times in 240 minutes

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.