Nafeesa graphed a line with a slope of 5 and a y-intercept of (0,-2) a. find an equation for her line. b. find the value of x when y=0

In this question , it is given that slope of 5 and a y-intercept of (0,-2) .

Now we have to check out the equation of the line that we are gonna use here.

Here we use the slope intercept form, which is

where m is the slope , which is 5 here and y intercept is b , which is -2 here.

Substituting these values in the equation, we will get

Part b .

Now we have to substitute 0 for y, and find the value of x, that is

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3