Find an equation that is parallel to y=5x+1 with points 5,8?

Line equation:

(y - yo) = m.(x - xo)

Where (xo, yo) is a point of this line and m his angular coeficient.

To a line be parallel to other their angular coeficient needs to be equal, in a line equation (y = ax + b) the angular coeficient is "a".

So, in y = 5x + 1, a = 5. So,

(y - yo) = 5.(x - xo)

Now, just put the point coordinates in xo and yo.

(y - 8) = 5.(x - 5)

y - 8 = 5x - 25

y = 5x - 25 + 8

y = 5x - 17

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

it will be a cylinder. with a diameter of 8 and 4 single pieces high

step-by-step explanation: