Solve the quadratic equations 2(x-2)^2+5=23

2(x-2)² + 5 = 23

2(x² - 4x + 4) + 5 = 23

2x² - 8x + 8 + 5 = 23

2x² - 8x + 13 = 23

2x² - 8x + 13 - 23 = 0

2x² - 8x - 10 = 0

2(x² - 4x - 5) = 0

Divide both sides by 2

x² - 4x - 5 = 0

Factor:

(x - 5)(x + 1) = 0

Set both factors equal to zero:

x - 5 = 0

x = 5

x + 1 = 0

x = - 1

Your answers are x = -1, 5 or at (-1, 0) and (5, 0).

oof

step-by-step explanation:

c.

step-by-step explanation:

simple you would first have to get   a negative number where as 1 to be multiplied by 24 and then you would have to multiply 6 time 4 and then repeat that process until you reach your term