Triangle pqr has vertices p(0,0), q(5,-2) and r(3-6).find the vertices of p’q’r after each translation. (8 units left and 1 unit down)

for a translation of point (x,y) by a units left & b units down,

the new coordinates are (x-a, y-b)

here

we move 8 units left and 1 unit down.

so a = -8 & b = -1

now for p(0,0)

p' (0-8, 0-1) = p'(-8,-1)

for q(5,-2)

q'(5-8, -2-1) = q'(-3,-3)

and for r(3, -6)

r'(3-8,-6-1) = r'(-5,-7)

the vertices are p'(-8,-1), q'(-3,-3) & r'(-5,-7)

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

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step-by-step explanation: