The length of a rectangle is 5 cm more than the width and the perimeter is 52 cm. find the length and width of the rectangle.

What is a perimeter? It's the area around. Think of a perimeter fence - that's the amount of fence you need to keep predators out of your land. The formula for perimeter is 2W + 2L (2 pieces of fence for each of the lengths and 2 pieces of fence for each of the widths).

The problem tells us that the L pieces are (2*W)+5

It also gives us the total, 34. Now we just need to plug in numbers.

2W + 2L = 34

2W + 2(2W+5)= 34 (we just substituted the value for L, given in the problem)

2W + 4W + 10 = 34 (distributed the 2 on the outside of the brackets)

Add the Ws:

6W + 10 = 34

Subtract 10 from each side:

6W = 24

Divide each side by 6:

W = 4

If the width is 4, we're told that the length is 5 more than twice the width, or (2*4)+5, which is 13.

Let's plug the numbers in to make certain.

2W + 2L = 34

2(4) + 2(13) = 34

8 + 26 does indeed equal 34.

Width = 4; length = 13

Hope this helps!

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

take it another