Mathematics, 13.07.2019 05:30 mariah10455

Sandy and robert each have various polygons in their polygon buckets. sandy randomly selects a polygon from her polygon bucket and robert randomly selects a polygon from his. a. who has a greater probability of selecting a quadrilateral? justify your conclusion. b. who has a greater probability of selecting an equilateral polygon? justify your conclusion. c. what is more likely to happen: sandy selecting a polygon with at least two sides that are parallel or robert selecting a polygon with at least two sides that are equal ? can anyone me with all this. i would appreciate it very much.

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Answer from: jacobmclawhorn3001

Solution:

we are given that

Sandy and Robert each have various polygons in their polygon buckets. Sandy randomly selects a polygon from her polygon bucket and Robert randomly selects a polygon from his.

A. who has a greater probability of selecting a quadrilateral? Justify your conclusion.

Sandy has greater proabaility(1/2) because in sandy bucket number of Quadrilaterals are more than the Robert(1/5). Also the number of polygon is less in case of Sandy. Hence greater proabaility for Sandy.

B. who has a greater probability of selecting an equilateral polygon? justify your conclusion.

Aagain sandy has greater probability because for sandy its 1/4 and for Robert its 1/5.

C. what is more likely to happen: Sandy selecting a polygon with at least two sides that are parallel or Robert selecting a polygon with at least two sides that are equal ?

Sandy has the probability of $\frac{2}{4}=\frac{1}{2}$ , while RFobert has the probability of $\frac{1}{5}$ . So again sany has greater probability.

Answer from: mkim2290

(A)

Number of Quadrilateral in Sandy Bucket =[Square,Rhombus]=2

Number of Quadrilateral in Robert Bucket =[Kite,Quadrilateral]=2

Probability of an event

$=\frac{\text{Total Favorable Outcome}}{\text{Total Possible Outcome}}$

→Probability of Selecting a Quadrilateral by Sandy

$=\frac{2}{4}\\\\=0.50$

→Probability of Selecting a Quadrilateral by Robert

$=\frac{2}{5}\\\\=0.40$

Selecting a Quadrilateral by Sandy has more probability than Selecting a Quadrilateral by Robert.

(B)

Number of equilateral polygon in Sandy's Bag={Square, Equilateral Triangle,Regular Hexagon}

Probability of selecting an equilateral polygon by Sandy

$=\frac{3}{4}\\\\=0.75$

Number of equilateral polygon in Robert's Bag=0

Probability of selecting an equilateral polygon by Robert=0

So, Probability of selecting an equilateral polygon by Sandy is greater than selecting an equilateral polygon by Robert.

(C)

Selecting a polygon with at least two sides that are parallel

={Square, Rhombus,Regular Hexagon}

Selecting a polygon with at least two sides that are equal

={Isosceles Triangle, Right Isosceles Triangle,Kite}

Probability of Selecting a polygon with at least two sides that are parallel out of four geometrical shapes by Sandy

$=\frac{3}{4}\\\\=0.75$

Probability of Selecting a polygon with at least two sides that are parallel out of four geometrical shapes by Robert

$=\frac{3}{5}\\\\=0.6$

Selecting a polygon with at least two sides that are parallel by Sandy is more likely than Selecting a polygon with at least two sides that are equal by Robert.

Answer from: Quest

$a_{15}$ = 5