Find the equation of the line that is perpendicular to the line x = −5 and passes through the point (1, π). a) y = π b) y = πx c) y = 1/5πx d) y = −5πx

The line x = -5 is a vertical line, therefore the line perpendicular to this line is the horizontal line of the form y = a.

We know that it passes through the point (1, π) → x = 1, y = π.

Therefore we have A) y = π.

3030 ur welcome

step-by-step explanation:

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2