Which of the following are solutions to the equation below? check all that apply. x^2 + 4x + 4 = 12 a. x =- √2+12 b. x = √2+12 c. x = -2√3-2 d. x = -2√3+2 e. x = 2√3-2 f. x = 2√3+2

There are several ways in which we could answer this question. My choice is to actually solve the given quadratic equation, x^2 + 4x + 4 = 12.

Note that x^2 + 4x + 4 is a perfect square. Thus,

x^2 + 4x + 4 = 12 is the same as (x+2)^2 = 12, so that

x+2 = plus or minus √3*√4, or plus or minus 2√3.

Thus, the two real, unequal roots are

x = -2 + 2√3 and x = -2 - 2√3. These correspond to answer choices C and E.

if you mean

then it's c. 8, -7/3

but if you mean

then it is

center= (-2,0)

radius= sqrt2/2

step-by-step explanation: