The length of the second side of a triangle is 3cm shorter than the first side and the third side is twice as long as the first side. if the perimeter is 49 how long are the 3 sides

I like to setup a "Let" statement when solving this type of problem.

Let x = first side (since the other sides are defined by it)

x - 3 = second side (since it is 3 cm shorter - take it away - than the first side)

2x = third side (since it is twice - 2 times - the first side)

Then we are given the perimeter which is the sum of all the sides. So we create an equation as follows.

first side + second side + third side = perimeter

x + x - 3 + 2x = 49

Solve the equation: 4x - 3 = 49

4x = 52

x = 13

We've got the first side... use it to find the other sides

First side = 13 cm

Second side = 13 cm - 3 cm = 10 cm

Third side = 2 × 13 cm = 26 cm

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify