Find the value of n such that x2– 3x + n is a perfect square trinomial.

Hello!

First, a word to the wise: Please type x2– 3x + n as x^2– 3x + n. The " ^ " denotes exponentiation, whereas x2 is meaningless.

To make x^2– 3x + n into a perfect square trinomial, take half of the coefficient of x (that is, half of -3) and square the result:

x^2– 3x + (3/2)^2, or x^2– 3x + 9/4. The desired value of n is then 9/4.

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x