What is the solution to this system of linear equations 2s-3c=-6

So the system is:

For this, I will be using the substitution method. So firstly, subtract 2c on both sides of the second equation:

Next, substitute s in the first equation for (11-2c) and solve for c:

Now that we know the value of c, replace c with its value and solve for s in either equation:

In short, c = 4 and s = 3.

a reflection across the x-axis , followed by the by a reflection across the y-axis , and then a scale dilation of 0.5 .

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3