What is the solution to this system of linear equations 2s-3c=-6

So the system is:

For this, I will be using the substitution method. So firstly, subtract 2c on both sides of the second equation:

Next, substitute s in the first equation for (11-2c) and solve for c:

Now that we know the value of c, replace c with its value and solve for s in either equation:

In short, c = 4 and s = 3.

-2 is the right

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.